What is the answer to 0=(2x-1)/(x^2-4) ?

The answer to 0=(2x-1)/(x^2-4) is x= 1/2

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0=(2x-1)/(x^2-4)

0 = \frac{2 x - 1}{x ^{2} - 4}

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

0 = \frac{2 x - 1}{x ^{2} - 4}

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

0 = 2 x - 1

Switch sides

2 x - 1 = 0

Move

1

to the right side

2 x = 1

Divide both sides by

2

x = \frac{1}{2}

Verify Solutions

Find undefined (singularity) points:

x = 2, x = - 2

Combine undefined points with solutions:

x = \frac{1}{2}

\frac{6}{x + 6} = \frac{8}{x}

170 = \frac{343}{2 \cdot l}

\frac{1}{x + 2} = \frac{1}{x} + \frac{1}{2}

4 π r + \frac{2}{r ^{2}} = 0

\frac{9}{x + 1} = \frac{2}{x ^{2} - 1}

What is the answer to 0=(2x-1)/(x^2-4) ?
The answer to 0=(2x-1)/(x^2-4) is x= 1/2
Solve for x: 0=(2x-1)/(x^2-4)
The solution is x= 1/2