What is the answer to 9/(x+1)= 2/(x^2-1) ?

The answer to 9/(x+1)= 2/(x^2-1) is x= 11/9

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9/(x+1)= 2/(x^2-1)

\frac{9}{x + 1} = \frac{2}{x ^{2} - 1}

x = \frac{11}{9}

Decimal Notation

x = 1.22222 \dots

Solution steps

\frac{9}{x + 1} = \frac{2}{x ^{2} - 1}

Cross multiply

9 (x^{2} - 1) = (x + 1) \cdot 2

Solve

9 (x^{2} - 1) = (x + 1) \cdot 2 : x = - 1, x = \frac{11}{9}

x = - 1, x = \frac{11}{9}

Verify Solutions

Find undefined (singularity) points:

x = - 1, x = 1

Since the equation is undefined for:

- 1

x = \frac{11}{9}

y, x = \frac{y + 1}{y - 1}

x, \frac{8}{x + 8} = \frac{7}{x + 4}

\frac{2}{( 1 - a )} = 3

y, \frac{3 y - 2 x}{2 y - 3 x} = 0

\frac{a}{x} - \frac{7}{x} = 5 - b

What is the answer to 9/(x+1)= 2/(x^2-1) ?
The answer to 9/(x+1)= 2/(x^2-1) is x= 11/9
Solve for x: 9/(x+1)= 2/(x^2-1)
The solution is x= 11/9