What are the solutions to the equation (x+4)^2=9 ?

The solutions to the equation (x+4)^2=9 are x=-1,x=-7

Find the zeros of (x+4)^2=9

The zeros of (x+4)^2=9 are x=-1,x=-7

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(x + 4)^{2} = 9

x = - 1, x = - 7

Solution steps

(x + 4)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = 9 : x = - 1

Solve

x + 4 = - 9 : x = - 7

The solutions to the quadratic equation are:

x = - 1, x = - 7

x^{3} + 12 x^{2} + 27 x

\frac{( 5 - 4 i ) - ( 3 + 7 i )}{( 4 + 2 i ) + ( 2 - 3 i )}

(t - 5)^{2} = (t + 5)^{2} + 60

25 n^{2} - 4

(7 k - 1)^{2} = - 125

What are the solutions to the equation (x+4)^2=9 ?
The solutions to the equation (x+4)^2=9 are x=-1,x=-7
Find the zeros of (x+4)^2=9
The zeros of (x+4)^2=9 are x=-1,x=-7