What is ((5-4i)-(3+7i))/((4+2i)+(2-3i)) ?

The solution to ((5-4i)-(3+7i))/((4+2i)+(2-3i)) is 23/37-64/37 i

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simplify ((5-4i)-(3+7i))/((4+2i)+(2-3i))

simplify

\frac{( 5 - 4 i ) - ( 3 + 7 i )}{( 4 + 2 i ) + ( 2 - 3 i )}

\frac{23}{37} - \frac{64}{37} i

Solution steps

\frac{( 5 - 4 i ) - ( 3 + 7 i )}{( 4 + 2 i ) + ( 2 - 3 i )}

Simplify

\frac{( 5 - 4 i ) - ( 3 + 7 i )}{( 4 + 2 i ) + ( 2 - 3 i )} : \frac{5 - 4 i - ( 3 + 7 i )}{4 + 2 i + 2 - 3 i}

= \frac{5 - 4 i - ( 3 + 7 i )}{4 + 2 i + 2 - 3 i}

Simplify

5 - 4 i - (3 + 7 i) : - 11 i + 2

= \frac{- 11 i + 2}{4 + 2 i + 2 - 3 i}

Simplify

4 + 2 i + 2 - 3 i : - i + 6

= \frac{- 11 i + 2}{- i + 6}

Rewrite

- 11 i + 2

in standard complex form:

2 - 11 i

Rewrite

- i + 6

in standard complex form:

6 - i

= \frac{2 - 11 i}{6 - i}

Multiply by the conjugate

\frac{6 + i}{6 + i}

= \frac{( 2 - 11 i ) ( 6 + i )}{( 6 - i ) ( 6 + i )}

Simplify

\frac{( 2 - 11 i ) ( 6 + i )}{( 6 - i ) ( 6 + i )} : \frac{23 - 64 i}{37}

= \frac{23 - 64 i}{37}

Rewrite in standard complex form:

\frac{23}{37} - \frac{64}{37} i

= \frac{23}{37} - \frac{64}{37} i

(t - 5)^{2} = (t + 5)^{2} + 60

25 n^{2} - 4

(7 k - 1)^{2} = - 125

4 x^{2} - 2 x + 15 = 0

2 x^{2} - 13 x = 7

What is ((5-4i)-(3+7i))/((4+2i)+(2-3i)) ?
The solution to ((5-4i)-(3+7i))/((4+2i)+(2-3i)) is 23/37-64/37 i