What is the answer to solvefor y,x=(y+1)/(y-1) ?

The answer to solvefor y,x=(y+1)/(y-1) is y=(1+x)/(x-1);\quad x\ne 1

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solvefor y,x=(y+1)/(y-1)

solve for

y, x = \frac{y + 1}{y - 1}

y = \frac{1 + x}{x - 1}; x \neq = 1

Solution steps

x = \frac{y + 1}{y - 1}

Multiply both sides by

y - 1

x (y - 1) = y + 1

Expand

x (y - 1) : y x - x

y x - x = y + 1

Move

x

to the right side

y x = y + 1 + x

Move

y

to the left side

y x - y = 1 + x

Factor

y x - y : y (x - 1)

y (x - 1) = 1 + x

Divide both sides by

x - 1; x \neq = 1

y = \frac{1 + x}{x - 1}; x \neq = 1

x, \frac{8}{x + 8} = \frac{7}{x + 4}

\frac{2}{( 1 - a )} = 3

y, \frac{3 y - 2 x}{2 y - 3 x} = 0

\frac{a}{x} - \frac{7}{x} = 5 - b

\frac{10}{x - 5} + x = 1 + \frac{2 x}{x - 5}

What is the answer to solvefor y,x=(y+1)/(y-1) ?
The answer to solvefor y,x=(y+1)/(y-1) is y=(1+x)/(x-1);\quad x\ne 1