What is the answer to solvefor y,(3y-2x)/(2y-3x)=0 ?

The answer to solvefor y,(3y-2x)/(2y-3x)=0 is y=(2x)/3

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solvefor y,(3y-2x)/(2y-3x)=0

solve for

y, \frac{3 y - 2 x}{2 y - 3 x} = 0

y = \frac{2 x}{3}

Solution steps

\frac{3 y - 2 x}{2 y - 3 x} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

3 y - 2 x = 0

Move

2 x

to the right side

3 y = 2 x

Divide both sides by

3

y = \frac{2 x}{3}

\frac{a}{x} - \frac{7}{x} = 5 - b

\frac{10}{x - 5} + x = 1 + \frac{2 x}{x - 5}

\frac{x}{x - 1} + \frac{x}{x + 1} = 2 \frac{2}{3}

\frac{x ^{2}}{4} = \frac{2}{x ^{2} + 1}

\frac{1}{4 x ^{2}} = \frac{1}{2 x - ( \frac{3}{4 x ^{2}} )}

What is the answer to solvefor y,(3y-2x)/(2y-3x)=0 ?
The answer to solvefor y,(3y-2x)/(2y-3x)=0 is y=(2x)/3