What is the answer to (x^2-x)/(x+2)=(2x-4)/(x-2) ?

The answer to (x^2-x)/(x+2)=(2x-4)/(x-2) is x=4,x=-1

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(x^2-x)/(x+2)=(2x-4)/(x-2)

\frac{x ^{2} - x}{x + 2} = \frac{2 x - 4}{x - 2}

x = 4, x = - 1

Solution steps

\frac{x ^{2} - x}{x + 2} = \frac{2 x - 4}{x - 2}

Simplify

\frac{2 x - 4}{x - 2} : 2

\frac{x ^{2} - x}{x + 2} = 2

Multiply both sides by

x + 2

x^{2} - x = 2 (x + 2)

Solve

x^{2} - x = 2 (x + 2) : x = 4, x = - 1

x = 4, x = - 1

Verify Solutions

Find undefined (singularity) points:

x = - 2, x = 2

Combine undefined points with solutions:

x = 4, x = - 1

2 - \frac{8}{x ^{2}} = 0

\frac{4.5351}{398.15} = \frac{3.8}{x}

\frac{x + 4}{4 x + 7} = \frac{x - 3}{x ^{2} - x - 6}

\frac{3 x - 1}{6 x - 2} = \frac{2 x + 5}{4 x - 13}

\frac{3 a}{x} - \frac{2 x}{a} = 1

What is the answer to (x^2-x)/(x+2)=(2x-4)/(x-2) ?
The answer to (x^2-x)/(x+2)=(2x-4)/(x-2) is x=4,x=-1
Solve for x: (x^2-x)/(x+2)=(2x-4)/(x-2)
The solution is x=4,x=-1