What are the solutions to the equation 4x^2-2x+15=0 ?

The solutions to the equation 4x^2-2x+15=0 are x= 1/4+i(sqrt(59))/4 ,x= 1/4-i(sqrt(59))/4

Find the zeros of 4x^2-2x+15=0

The zeros of 4x^2-2x+15=0 are x= 1/4+i(sqrt(59))/4 ,x= 1/4-i(sqrt(59))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} - 2 x + 15 = 0

x = \frac{1}{4} + i \frac{59}{4}, x = \frac{1}{4} - i \frac{59}{4}

Solution steps

4 x^{2} - 2 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 4 \cdot 15}{2 \cdot 4}

Simplify

(- 2)^{2} - 4 \cdot 4 \cdot 15 : 259 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 59 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 59 i}{2 \cdot 4}, x_{2} = \frac{- ( - 2 ) - 2 59 i}{2 \cdot 4}

x = \frac{- ( - 2 ) + 2 59 i}{2 \cdot 4} : \frac{1}{4} + i \frac{59}{4}

x = \frac{- ( - 2 ) - 2 59 i}{2 \cdot 4} : \frac{1}{4} - i \frac{59}{4}

The solutions to the quadratic equation are:

x = \frac{1}{4} + i \frac{59}{4}, x = \frac{1}{4} - i \frac{59}{4}

2 x^{2} - 13 x = 7

(\frac{1}{2} + \frac{3}{2} i)^{6}

10 x^{2} - 20 x - 10 = 0

(- \frac{4}{7})^{4}

a^{- 3}

What are the solutions to the equation 4x^2-2x+15=0 ?
The solutions to the equation 4x^2-2x+15=0 are x= 1/4+i(sqrt(59))/4 ,x= 1/4-i(sqrt(59))/4
Find the zeros of 4x^2-2x+15=0
The zeros of 4x^2-2x+15=0 are x= 1/4+i(sqrt(59))/4 ,x= 1/4-i(sqrt(59))/4