What is the answer to 8^{1+x}+2^{3x-1}= 17/16 ?

The answer to 8^{1+x}+2^{3x-1}= 17/16 is x=-1

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8^{1+x}+2^{3x-1}= 17/16

8^{1 + x} + 2^{3 x - 1} = \frac{17}{16}

x = - 1

Solution steps

8^{1 + x} + 2^{3 x - 1} = \frac{17}{16}

Apply exponent rules

3 x = - 3

Solve

3 x = - 3 : x = - 1

x = - 1

\frac{4 ^{x + 1}}{2 ^{x + 2}} = 186

e^{a x}

2^{x + 1} - 2^{- x + 2} = 7

4^{3 x - 2} = 1

7^{x} = 4^{2 x - 1}

What is the answer to 8^{1+x}+2^{3x-1}= 17/16 ?
The answer to 8^{1+x}+2^{3x-1}= 17/16 is x=-1
Solve for x: 8^{1+x}+2^{3x-1}= 17/16
The solution is x=-1