What is the answer to 7^{3x}=3^{2-x} ?

The answer to 7^{3x}=3^{2-x} is x=(2ln(3))/(ln(1029))

Solve for x: 7^{3x}=3^{2-x}

The solution is x=(2ln(3))/(ln(1029))

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7^{3 x} = 3^{2 - x}

x = \frac{2 ln ( 3 )}{ln ( 1029 )}

Decimal Notation

x = 0.31676 \dots

Solution steps

7^{3 x} = 3^{2 - x}

Apply exponent rules

3 x ln (7) = (2 - x) ln (3)

Solve

3 x ln (7) = (2 - x) ln (3) : x = \frac{2 ln ( 3 )}{ln ( 1029 )}

x = \frac{2 ln ( 3 )}{ln ( 1029 )}

x, 3^{2 x} + 2 \cdot 3^{x + 1} = 16

5^{2 x - 3} = 3^{3 x + 4}

2 x e^{x^{2}} = 0

4^{x^{2} + 2} - 9 \cdot 2^{x^{2} + 2} + 8 = 0

5^{3 x} = 33 (7^{x})

What is the answer to 7^{3x}=3^{2-x} ?
The answer to 7^{3x}=3^{2-x} is x=(2ln(3))/(ln(1029))
Solve for x: 7^{3x}=3^{2-x}
The solution is x=(2ln(3))/(ln(1029))