What is the answer to 11^{x+6}=3^x ?

The answer to 11^{x+6}=3^x is x=-(6ln(11))/(ln(11)-ln(3))

Solve for x: 11^{x+6}=3^x

The solution is x=-(6ln(11))/(ln(11)-ln(3))

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1 1^{x + 6} = 3^{x}

x = - \frac{6 ln ( 11 )}{ln ( 11 ) - ln ( 3 )}

Decimal Notation

x = - 11.07331 \dots

Solution steps

1 1^{x + 6} = 3^{x}

Apply exponent rules

(x + 6) ln (11) = x ln (3)

Solve

(x + 6) ln (11) = x ln (3) : x = - \frac{6 ln ( 11 )}{ln ( 11 ) - ln ( 3 )}

x = - \frac{6 ln ( 11 )}{ln ( 11 ) - ln ( 3 )}

4 x e^{x} = 2

2^{\frac{1}{2}} = 4 e^{- \frac{t}{0.00001}}

3^{20 - x} = 9

5 \times 2^{x + 1} = 15

t, A = P e^{r t}

What is the answer to 11^{x+6}=3^x ?
The answer to 11^{x+6}=3^x is x=-(6ln(11))/(ln(11)-ln(3))
Solve for x: 11^{x+6}=3^x
The solution is x=-(6ln(11))/(ln(11)-ln(3))