What is the answer to 2^{x+1}+2^{x+2}+2^{x+3}=112 ?

The answer to 2^{x+1}+2^{x+2}+2^{x+3}=112 is x=3

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2^{x+1}+2^{x+2}+2^{x+3}=112

2^{x + 1} + 2^{x + 2} + 2^{x + 3} = 112

x = 3

Solution steps

2^{x + 1} + 2^{x + 2} + 2^{x + 3} = 112

Factor

2^{x + 1} + 2^{x + 2} + 2^{x + 3} : 7 \cdot 2^{x + 1}

7 \cdot 2^{x + 1} = 112

Divide both sides by

7

2^{x + 1} = 16

Apply exponent rules

x + 1 = 4

Solve

x + 1 = 4 : x = 3

x = 3

4^{2 x + 3} = 5^{x - 2}

x, 5 e^{x} - 9 cos x = 2

2^{2 z - 2} + 2^{z + 2} = 48

1 - 2 e^{- 2 x} = 0

9^{x} + 3 = 28

What is the answer to 2^{x+1}+2^{x+2}+2^{x+3}=112 ?
The answer to 2^{x+1}+2^{x+2}+2^{x+3}=112 is x=3
Solve for x: 2^{x+1}+2^{x+2}+2^{x+3}=112
The solution is x=3