What is the answer to 17/327 =e^{-9.22\times 10^{-4}t} ?

The answer to 17/327 =e^{-9.22\times 10^{-4}t} is t=-(10000ln(17/327))/(9.22)

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17/327 =e^{-9.22\times 10^{-4}t}

\frac{17}{327} = e^{- 9.22 \cdot 1 0^{- 4} t}

t = - \frac{10000 ln ( \frac{17}{327} )}{9.22}

Decimal Notation

t = 3206.88376 \dots

Solution steps

\frac{17}{327} = e^{- 9.22 \cdot 1 0^{- 4} t}

Apply exponent rules

ln (\frac{17}{327}) = - 9.22 \cdot 1 0^{- 4} t

Solve

ln (\frac{17}{327}) = - 9.22 \cdot 1 0^{- 4} t : t = - \frac{10000 ln ( \frac{17}{327} )}{9.22}

t = - \frac{10000 ln ( \frac{17}{327} )}{9.22}

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What is the answer to 17/327 =e^{-9.22\times 10^{-4}t} ?
The answer to 17/327 =e^{-9.22\times 10^{-4}t} is t=-(10000ln(17/327))/(9.22)