What is the answer to 9^{x+2}=27^{-x} ?

The answer to 9^{x+2}=27^{-x} is x=-4/5

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9^{x+2}=27^{-x}

9^{x + 2} = 2 7^{- x}

x = - \frac{4}{5}

Decimal Notation

x = - 0.8

Solution steps

9^{x + 2} = 2 7^{- x}

Apply exponent rules

2 (x + 2) = - 3 x

Solve

2 (x + 2) = - 3 x : x = - \frac{4}{5}

x = - \frac{4}{5}

- 24 \times 3^{x - 1} + 9^{x} = 9

7^{- x} = 49

6 = 34.416 e^{- 0.18 (t)}

(1 + x^{2}) 2^{x} - 5 \cdot 2^{x} = 0

t, 8000 = 245 t + 6125 e^{- 0.04 t}