What is the answer to 3(4^{2-x})=30 ?

The answer to 3(4^{2-x})=30 is x=(ln(8/5))/(2ln(2))

Solve for x: 3(4^{2-x})=30

The solution is x=(ln(8/5))/(2ln(2))

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3 (4^{2 - x}) = 30

x = \frac{ln ( \frac{8}{5} )}{2 ln ( 2 )}

Decimal Notation

x = 0.33903 \dots

Solution steps

3 (4^{2 - x}) = 30

Divide both sides by

3

4^{2 - x} = 10

Apply exponent rules

(2 - x) ln (4) = ln (10)

Solve

(2 - x) ln (4) = ln (10) : x = \frac{ln ( \frac{8}{5} )}{2 ln ( 2 )}

x = \frac{ln ( \frac{8}{5} )}{2 ln ( 2 )}

6^{5 x} = 4^{(3 - 2 x)}

4^{x} + 4^{x + 1} = 40

e^{5 x + 3} = 1

x^{2} 3^{x} - 3^{x + 2} = 0

16 \cdot 2^{6 m} = 2^{3 m - 8}

What is the answer to 3(4^{2-x})=30 ?
The answer to 3(4^{2-x})=30 is x=(ln(8/5))/(2ln(2))
Solve for x: 3(4^{2-x})=30
The solution is x=(ln(8/5))/(2ln(2))