What is the answer to 6^{5x}=4^{(3-2x)} ?

The answer to 6^{5x}=4^{(3-2x)} is x=(6ln(2))/(5ln(6)+4ln(2))

Solve for x: 6^{5x}=4^{(3-2x)}

The solution is x=(6ln(2))/(5ln(6)+4ln(2))

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6^{5 x} = 4^{(3 - 2 x)}

x = \frac{6 ln ( 2 )}{5 ln ( 6 ) + 4 ln ( 2 )}

Decimal Notation

x = 0.35450 \dots

Solution steps

6^{5 x} = 4^{(3 - 2 x)}

Apply exponent rules

5 x ln (6) = (3 - 2 x) ln (4)

Solve

5 x ln (6) = (3 - 2 x) ln (4) : x = \frac{6 ln ( 2 )}{5 ln ( 6 ) + 4 ln ( 2 )}

x = \frac{6 ln ( 2 )}{5 ln ( 6 ) + 4 ln ( 2 )}

4^{x} + 4^{x + 1} = 40

e^{5 x + 3} = 1

x^{2} 3^{x} - 3^{x + 2} = 0

16 \cdot 2^{6 m} = 2^{3 m - 8}

2^{5 - 7 x} = 15

What is the answer to 6^{5x}=4^{(3-2x)} ?
The answer to 6^{5x}=4^{(3-2x)} is x=(6ln(2))/(5ln(6)+4ln(2))
Solve for x: 6^{5x}=4^{(3-2x)}
The solution is x=(6ln(2))/(5ln(6)+4ln(2))