What is the answer to 2^{5-7x}=15 ?

The answer to 2^{5-7x}=15 is x=(-ln(15)+5ln(2))/(7ln(2))

Solve for x: 2^{5-7x}=15

The solution is x=(-ln(15)+5ln(2))/(7ln(2))

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2^{5 - 7 x} = 15

x = \frac{- ln ( 15 ) + 5 ln ( 2 )}{7 ln ( 2 )}

Decimal Notation

x = 0.15615 \dots

Solution steps

2^{5 - 7 x} = 15

Apply exponent rules

(5 - 7 x) ln (2) = ln (15)

Solve

(5 - 7 x) ln (2) = ln (15) : x = \frac{- ln ( 15 ) + 5 ln ( 2 )}{7 ln ( 2 )}

x = \frac{- ln ( 15 ) + 5 ln ( 2 )}{7 ln ( 2 )}

4^{x^{2} + 1} = 2^{5 x + 5}

x^{3} = 1. 5^{x}

4^{x + 2} - 3 \times 2^{x + 3} = 160

e^{x^{2}} \cdot 2 x = 0

3 (5^{x - 1}) = 21

What is the answer to 2^{5-7x}=15 ?
The answer to 2^{5-7x}=15 is x=(-ln(15)+5ln(2))/(7ln(2))
Solve for x: 2^{5-7x}=15
The solution is x=(-ln(15)+5ln(2))/(7ln(2))