What is the answer to 3(5^{x-1})=21 ?

The answer to 3(5^{x-1})=21 is x=(ln(7))/(ln(5))+1

Solve for x: 3(5^{x-1})=21

The solution is x=(ln(7))/(ln(5))+1

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3 (5^{x - 1}) = 21

x = \frac{ln ( 7 )}{ln ( 5 )} + 1

Decimal Notation

x = 2.20906 \dots

Solution steps

3 (5^{x - 1}) = 21

Divide both sides by

3

5^{x - 1} = 7

Apply exponent rules

(x - 1) ln (5) = ln (7)

Solve

(x - 1) ln (5) = ln (7) : x = \frac{ln ( 7 )}{ln ( 5 )} + 1

x = \frac{ln ( 7 )}{ln ( 5 )} + 1

4 \cdot 1 0^{2 - x} = 15

2^{2 x} + 2^{x} - 56 = 0

\frac{1}{125} = 2 5^{x + 5}

6^{8 x + 5} = 5^{x - 3}

7^{2 x - 3} = 21

What is the answer to 3(5^{x-1})=21 ?
The answer to 3(5^{x-1})=21 is x=(ln(7))/(ln(5))+1
Solve for x: 3(5^{x-1})=21
The solution is x=(ln(7))/(ln(5))+1