What is the answer to 4*10^{2-x}=15 ?

The answer to 4*10^{2-x}=15 is x=(ln(80/3))/(ln(10))

Solve for x: 4*10^{2-x}=15

The solution is x=(ln(80/3))/(ln(10))

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4 \cdot 1 0^{2 - x} = 15

x = \frac{ln ( \frac{80}{3} )}{ln ( 10 )}

Decimal Notation

x = 1.42596 \dots

Solution steps

4 \cdot 1 0^{2 - x} = 15

Divide both sides by

4

1 0^{2 - x} = \frac{15}{4}

Apply exponent rules

(2 - x) ln (10) = ln (\frac{15}{4})

Solve

(2 - x) ln (10) = ln (\frac{15}{4}) : x = \frac{ln ( \frac{80}{3} )}{ln ( 10 )}

x = \frac{ln ( \frac{80}{3} )}{ln ( 10 )}

2^{2 x} + 2^{x} - 56 = 0

\frac{1}{125} = 2 5^{x + 5}

6^{8 x + 5} = 5^{x - 3}

7^{2 x - 3} = 21

5^{x - 3} = 25

What is the answer to 4*10^{2-x}=15 ?
The answer to 4*10^{2-x}=15 is x=(ln(80/3))/(ln(10))
Solve for x: 4*10^{2-x}=15
The solution is x=(ln(80/3))/(ln(10))