What is the answer to 4^{-2x}=7 ?

The answer to 4^{-2x}=7 is x=-(ln(7))/(4ln(2))

Solve for x: 4^{-2x}=7

The solution is x=-(ln(7))/(4ln(2))

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4^{- 2 x} = 7

x = - \frac{ln ( 7 )}{4 ln ( 2 )}

Decimal Notation

x = - 0.70183 \dots

Solution steps

4^{- 2 x} = 7

Apply exponent rules

- 2 x ln (4) = ln (7)

Solve

- 2 x ln (4) = ln (7) : x = - \frac{ln ( 7 )}{4 ln ( 2 )}

x = - \frac{ln ( 7 )}{4 ln ( 2 )}

2^{6 x} = 0.125

1 6^{x} = x^{8}

6^{3 x - 1} = 3 6^{x + 4}

9^{x + 1} + 3 = 28 \times 3^{x}

4^{2 x} = 4^{- 2 x - 1}

What is the answer to 4^{-2x}=7 ?
The answer to 4^{-2x}=7 is x=-(ln(7))/(4ln(2))
Solve for x: 4^{-2x}=7
The solution is x=-(ln(7))/(4ln(2))