What is the answer to 4^{2x}=4^{-2x-1} ?

The answer to 4^{2x}=4^{-2x-1} is x=-1/4

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4^{2x}=4^{-2x-1}

4^{2 x} = 4^{- 2 x - 1}

x = - \frac{1}{4}

Decimal Notation

x = - 0.25

Solution steps

4^{2 x} = 4^{- 2 x - 1}

Apply exponent rules

2 x = - 2 x - 1

Solve

2 x = - 2 x - 1 : x = - \frac{1}{4}

x = - \frac{1}{4}

e^{2 x} + 9 - e^{2 x} - 4 = 1

\frac{e ^{4 x + 7}}{3} + 1 = 12

3 \cdot 9^{x} \cdot 2 7^{x} = 1

3^{3 x - 4} = 24 3^{x}

3^{2 x + 1} - 5 = 11

What is the answer to 4^{2x}=4^{-2x-1} ?
The answer to 4^{2x}=4^{-2x-1} is x=-1/4
Solve for x: 4^{2x}=4^{-2x-1}
The solution is x=-1/4