What is the answer to (1/5)^x\times 125^{x+1}=4 ?

The answer to (1/5)^x\times 125^{x+1}=4 is x=(ln(4/125))/(2ln(5))

Solve for x: (1/5)^x\times 125^{x+1}=4

The solution is x=(ln(4/125))/(2ln(5))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\frac{1}{5})^{x} \cdot 12 5^{x + 1} = 4

x = \frac{ln ( \frac{4}{125} )}{2 ln ( 5 )}

Decimal Notation

x = - 1.06932 \dots

Solution steps

(\frac{1}{5})^{x} \cdot 12 5^{x + 1} = 4

Apply exponent rules

x ln (25) = ln (\frac{4}{125})

Solve

x ln (25) = ln (\frac{4}{125}) : x = \frac{ln ( \frac{4}{125} )}{2 ln ( 5 )}

x = \frac{ln ( \frac{4}{125} )}{2 ln ( 5 )}

(\frac{1}{2})^{4 x - 2} = 2^{x - 2}

1 8^{2 x} \cdot 3^{- 2 x} = 6

2^{- 3 n} \cdot \frac{1}{4} = 2^{n + 2}

e^{- x} = 0.5

(1.01 2^{t - 1998}) = 1.1707

What is the answer to (1/5)^x\times 125^{x+1}=4 ?
The answer to (1/5)^x\times 125^{x+1}=4 is x=(ln(4/125))/(2ln(5))
Solve for x: (1/5)^x\times 125^{x+1}=4
The solution is x=(ln(4/125))/(2ln(5))