What is the answer to 2^{2x}-3*2^x=-2 ?

The answer to 2^{2x}-3*2^x=-2 is x=1,x=0

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2^{2x}-3*2^x=-2

2^{2 x} - 3 \cdot 2^{x} = - 2

x = 1, x = 0

Solution steps

2^{2 x} - 3 \cdot 2^{x} = - 2

Apply exponent rules

(2^{x})^{2} - 3 \cdot 2^{x} = - 2

Rewrite the equation with

2^{x} = u

(u)^{2} - 3 u = - 2

Solve

u^{2} - 3 u = - 2 : u = 2, u = 1

u = 2, u = 1

Substitute back

u = 2^{x},

solve for

x

Solve

2^{x} = 2 : x = 1

Solve

2^{x} = 1 : x = 0

x = 1, x = 0

k, \frac{n}{2 ^{k}} = 1

6 4^{- x + 26} = 12 8^{x}

5^{x} = 6^{x - 1}

3 e^{2 x} - 4 e^{- 2 x} = 5

2^{x^{2} - 3} = \frac{1}{4}

What is the answer to 2^{2x}-3*2^x=-2 ?
The answer to 2^{2x}-3*2^x=-2 is x=1,x=0
Solve for x: 2^{2x}-3*2^x=-2
The solution is x=1,x=0