What is the answer to 5(2)^{x+1}=9 ?

The answer to 5(2)^{x+1}=9 is x=(ln(9/5))/(ln(2))-1

Solve for x: 5(2)^{x+1}=9

The solution is x=(ln(9/5))/(ln(2))-1

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5 (2)^{x + 1} = 9

x = \frac{ln ( \frac{9}{5} )}{ln ( 2 )} - 1

Decimal Notation

x = - 0.15200 \dots

Solution steps

5 (2)^{x + 1} = 9

Divide both sides by

5

2^{x + 1} = \frac{9}{5}

Apply exponent rules

(x + 1) ln (2) = ln (\frac{9}{5})

Solve

(x + 1) ln (2) = ln (\frac{9}{5}) : x = \frac{ln ( \frac{9}{5} )}{ln ( 2 )} - 1

x = \frac{ln ( \frac{9}{5} )}{ln ( 2 )} - 1

7 e^{9 x} = 20

9^{3 x} = 2 7^{x - 2}

\frac{2 ^{4 x - 1}}{2 ^{3 x + 2}} = 16

3^{x - 1} - 3^{x} + 3^{x + 1} = 63

5^{9 x - 12} = 2 5^{x}

What is the answer to 5(2)^{x+1}=9 ?
The answer to 5(2)^{x+1}=9 is x=(ln(9/5))/(ln(2))-1
Solve for x: 5(2)^{x+1}=9
The solution is x=(ln(9/5))/(ln(2))-1