What is the answer to 5^{x-4}=3^{2x} ?

The answer to 5^{x-4}=3^{2x} is x=(4ln(5))/(ln(5)-2ln(3))

Solve for x: 5^{x-4}=3^{2x}

The solution is x=(4ln(5))/(ln(5)-2ln(3))

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5^{x - 4} = 3^{2 x}

x = \frac{4 ln ( 5 )}{ln ( 5 ) - 2 ln ( 3 )}

Solution steps

5^{x - 4} = 3^{2 x}

Apply exponent rules

(x - 4) ln (5) = 2 x ln (3)

Solve

(x - 4) ln (5) = 2 x ln (3) : x = \frac{4 ln ( 5 )}{ln ( 5 ) - 2 ln ( 3 )}

x = \frac{4 ln ( 5 )}{ln ( 5 ) - 2 ln ( 3 )}

3^{2 x} (3^{2 x - 1})^{3} = 9

e^{- x} x^{4} - 8 e^{- x} x^{3} + 12 e^{- x} x^{2} = 0

3^{x} = 5^{2 x}

x, 9^{5 + 2 z} = x

4^{5 x - 2} = 3^{- 2 x + 1}

What is the answer to 5^{x-4}=3^{2x} ?
The answer to 5^{x-4}=3^{2x} is x=(4ln(5))/(ln(5)-2ln(3))
Solve for x: 5^{x-4}=3^{2x}
The solution is x=(4ln(5))/(ln(5)-2ln(3))