(2^{x^2})/(4^x)=16

الحلّ

\frac{2 ^{x^{2}}}{4 ^{x}} = 16

x = 1 + 5, x = 1 - 5

خطوات الحلّ

\frac{2 ^{x^{2}}}{4 ^{x}} = 16

فعّل قانون القوى

x^{2} - 2 x = 4

x^{2} - 2 x = 4

حلّ:

x = 1 + 5, x = 1 - 5

x = 1 + 5, x = 1 - 5

افحص الإجبات:

x = 1 + 5

صحيح

, x = 1 - 5

صحيح

The solutions are

x = 1 + 5, x = 1 - 5

e^{- x} - x + 1 = 0

9^{x + 1} - 28 \cdot 3^{x} + 3 = 0

3 \cdot 6^{1 - x} = 15

500 e^{3 x + 2} = 15000

(\frac{1}{9})^{x - 5} = 3^{3 x}