What is the answer to (2^{x^2})/(4^x)=16 ?

The answer to (2^{x^2})/(4^x)=16 is x=1+sqrt(5),x=1-sqrt(5)

Solve for x: (2^{x^2})/(4^x)=16

The solution is x=1+sqrt(5),x=1-sqrt(5)

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\frac{2 ^{x^{2}}}{4 ^{x}} = 16

x = 1 + 5, x = 1 - 5

Decimal Notation

x = 3.23606 \dots, x = - 1.23606 \dots

Solution steps

\frac{2 ^{x^{2}}}{4 ^{x}} = 16

Apply exponent rules

x^{2} - 2 x = 4

Solve

x^{2} - 2 x = 4 : x = 1 + 5, x = 1 - 5

x = 1 + 5, x = 1 - 5

Verify Solutions:

x = 1 + 5

True

, x = 1 - 5

True

The solutions are

x = 1 + 5, x = 1 - 5

e^{- x} - x + 1 = 0

9^{x + 1} - 28 \cdot 3^{x} + 3 = 0

3 \cdot 6^{1 - x} = 15

500 e^{3 x + 2} = 15000

(\frac{1}{9})^{x - 5} = 3^{3 x}

What is the answer to (2^{x^2})/(4^x)=16 ?
The answer to (2^{x^2})/(4^x)=16 is x=1+sqrt(5),x=1-sqrt(5)
Solve for x: (2^{x^2})/(4^x)=16
The solution is x=1+sqrt(5),x=1-sqrt(5)