What is the answer to 3*6^{1-x}=15 ?

The answer to 3*6^{1-x}=15 is x=(-ln(5)+ln(6))/(ln(6))

Solve for x: 3*6^{1-x}=15

The solution is x=(-ln(5)+ln(6))/(ln(6))

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3 \cdot 6^{1 - x} = 15

x = \frac{- ln ( 5 ) + ln ( 6 )}{ln ( 6 )}

Decimal Notation

x = 0.10175 \dots

Solution steps

3 \cdot 6^{1 - x} = 15

Divide both sides by

3

6^{1 - x} = 5

Apply exponent rules

(1 - x) ln (6) = ln (5)

Solve

(1 - x) ln (6) = ln (5) : x = \frac{- ln ( 5 ) + ln ( 6 )}{ln ( 6 )}

x = \frac{- ln ( 5 ) + ln ( 6 )}{ln ( 6 )}

500 e^{3 x + 2} = 15000

(\frac{1}{9})^{x - 5} = 3^{3 x}

4^{x - x^{2}} = \frac{1}{1 6 ^{x}}

4^{x + 2} + 4^{x - 1} = \frac{65}{64}

6^{2 x} = 7^{x + 4}

What is the answer to 3*6^{1-x}=15 ?
The answer to 3*6^{1-x}=15 is x=(-ln(5)+ln(6))/(ln(6))
Solve for x: 3*6^{1-x}=15
The solution is x=(-ln(5)+ln(6))/(ln(6))