What is the answer to 6^{2x}=7^{x+4} ?

The answer to 6^{2x}=7^{x+4} is x=(4ln(7))/(2ln(6)-ln(7))

Solve for x: 6^{2x}=7^{x+4}

The solution is x=(4ln(7))/(2ln(6)-ln(7))

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6^{2 x} = 7^{x + 4}

x = \frac{4 ln ( 7 )}{2 ln ( 6 ) - ln ( 7 )}

Decimal Notation

x = 4.75305 \dots

Solution steps

6^{2 x} = 7^{x + 4}

Apply exponent rules

2 x ln (6) = (x + 4) ln (7)

Solve

2 x ln (6) = (x + 4) ln (7) : x = \frac{4 ln ( 7 )}{2 ln ( 6 ) - ln ( 7 )}

x = \frac{4 ln ( 7 )}{2 ln ( 6 ) - ln ( 7 )}

9^{x - 2} = 27

4^{3 x - 1} = 3 2^{- 4}

5^{x} = 8^{x}

1 + e^{x - 1} = 0

6^{x + 1} = 4^{2 x - 1}

What is the answer to 6^{2x}=7^{x+4} ?
The answer to 6^{2x}=7^{x+4} is x=(4ln(7))/(2ln(6)-ln(7))
Solve for x: 6^{2x}=7^{x+4}
The solution is x=(4ln(7))/(2ln(6)-ln(7))