What is the answer to 6^{x+1}=4^{2x-1} ?

The answer to 6^{x+1}=4^{2x-1} is x=(ln(24))/(ln(8/3))

Solve for x: 6^{x+1}=4^{2x-1}

The solution is x=(ln(24))/(ln(8/3))

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6^{x + 1} = 4^{2 x - 1}

x = \frac{ln ( 24 )}{ln ( \frac{8}{3} )}

Decimal Notation

x = 3.24017 \dots

Solution steps

6^{x + 1} = 4^{2 x - 1}

Apply exponent rules

(x + 1) ln (6) = (2 x - 1) ln (4)

Solve

(x + 1) ln (6) = (2 x - 1) ln (4) : x = \frac{ln ( 24 )}{ln ( \frac{8}{3} )}

x = \frac{ln ( 24 )}{ln ( \frac{8}{3} )}

3 6^{7 x + 1} = 21 6^{3 x - 2}

1 - 4 e^{- 4 x} = 0

4^{2 x} = 7

7^{1 + 2 x} - 50 \cdot 7^{x} + 7 = 0

1 3^{x} = 26

What is the answer to 6^{x+1}=4^{2x-1} ?
The answer to 6^{x+1}=4^{2x-1} is x=(ln(24))/(ln(8/3))
Solve for x: 6^{x+1}=4^{2x-1}
The solution is x=(ln(24))/(ln(8/3))