What is the answer to 36^{7x+1}=216^{3x-2} ?

The answer to 36^{7x+1}=216^{3x-2} is x=-8/5

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36^{7x+1}=216^{3x-2}

3 6^{7 x + 1} = 21 6^{3 x - 2}

x = - \frac{8}{5}

Decimal Notation

x = - 1.6

Solution steps

3 6^{7 x + 1} = 21 6^{3 x - 2}

Apply exponent rules

2 (7 x + 1) = 3 (3 x - 2)

Solve

2 (7 x + 1) = 3 (3 x - 2) : x = - \frac{8}{5}

x = - \frac{8}{5}

1 - 4 e^{- 4 x} = 0

4^{2 x} = 7

7^{1 + 2 x} - 50 \cdot 7^{x} + 7 = 0

1 3^{x} = 26

e^{x} x^{2} (x^{2} + x - 6) = 0

What is the answer to 36^{7x+1}=216^{3x-2} ?
The answer to 36^{7x+1}=216^{3x-2} is x=-8/5
Solve for x: 36^{7x+1}=216^{3x-2}
The solution is x=-8/5