What is the answer to 4^{2x}=7 ?

The answer to 4^{2x}=7 is x=(ln(7))/(4ln(2))

Solve for x: 4^{2x}=7

The solution is x=(ln(7))/(4ln(2))

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4^{2 x} = 7

x = \frac{ln ( 7 )}{4 ln ( 2 )}

Decimal Notation

x = 0.70183 \dots

Solution steps

4^{2 x} = 7

Apply exponent rules

2 x ln (4) = ln (7)

Solve

2 x ln (4) = ln (7) : x = \frac{ln ( 7 )}{4 ln ( 2 )}

x = \frac{ln ( 7 )}{4 ln ( 2 )}

7^{1 + 2 x} - 50 \cdot 7^{x} + 7 = 0

1 3^{x} = 26

e^{x} x^{2} (x^{2} + x - 6) = 0

t, E^{- 18 t} = \frac{15}{4}

6 (2^{3 x - 1}) - 7 = 9