What is the answer to cube root of 4^{x+2}}= 4/(\sqrt[5]{2) ?

The answer to cube root of 4^{x+2}}= 4/(\sqrt[5]{2) is x= 7/10

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cube root of 4^{x+2}}= 4/(\sqrt[5]{2)

x = \frac{7}{10}

Solution steps

Apply exponent rules

\frac{2}{3} (x + 2) = \frac{9}{5}

Solve

\frac{2}{3} (x + 2) = \frac{9}{5} : x = \frac{7}{10}

x = \frac{7}{10}

(300 \cdot 400) = 12 \cdot 1 0^{x}

n^{3} = 1. 5^{n}

3 e^{x + 1} - 5 = 7

1 0^{1 - 2 x} = 11

6 4^{x} = 128

What is the answer to cube root of 4^{x+2}}= 4/(\sqrt[5]{2) ?
The answer to cube root of 4^{x+2}}= 4/(\sqrt[5]{2) is x= 7/10
Solve for x: cube root of 4^{x+2}}= 4/(\sqrt[5]{2)
The solution is x= 7/10