What is the answer to 7^{x+5}=4 ?

The answer to 7^{x+5}=4 is x=(2ln(2))/(ln(7))-5

Solve for x: 7^{x+5}=4

The solution is x=(2ln(2))/(ln(7))-5

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7^{x + 5} = 4

x = \frac{2 ln ( 2 )}{ln ( 7 )} - 5

Solution steps

7^{x + 5} = 4

Apply exponent rules

(x + 5) ln (7) = ln (4)

Solve

(x + 5) ln (7) = ln (4) : x = \frac{2 ln ( 2 )}{ln ( 7 )} - 5

x = \frac{2 ln ( 2 )}{ln ( 7 )} - 5

9^{x} - 4 \times 3^{x} + 3 = 0

\frac{1000}{1 + 39 e ^{- 0.42 x}} = 630

3 = e^{2 x}

5 = a \times b^{- (x - c)} + d

1 6^{3 x - 2} = 3 2^{x + 4}

What is the answer to 7^{x+5}=4 ?
The answer to 7^{x+5}=4 is x=(2ln(2))/(ln(7))-5
Solve for x: 7^{x+5}=4
The solution is x=(2ln(2))/(ln(7))-5