What is the answer to 3^{x-5}=64*4^x ?

The answer to 3^{x-5}=64*4^x is x=(6ln(2)+5ln(3))/(ln(3)-2ln(2))

Solve for x: 3^{x-5}=64*4^x

The solution is x=(6ln(2)+5ln(3))/(ln(3)-2ln(2))

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3^{x - 5} = 64 \cdot 4^{x}

x = \frac{6 ln ( 2 ) + 5 ln ( 3 )}{ln ( 3 ) - 2 ln ( 2 )}

Decimal Notation

x = - 33.55073 \dots

Solution steps

3^{x - 5} = 64 \cdot 4^{x}

Apply exponent rules

(x - 5) ln (3) = ln (64) + x ln (4)

Solve

(x - 5) ln (3) = ln (64) + x ln (4) : x = \frac{6 ln ( 2 ) + 5 ln ( 3 )}{ln ( 3 ) - 2 ln ( 2 )}

x = \frac{6 ln ( 2 ) + 5 ln ( 3 )}{ln ( 3 ) - 2 ln ( 2 )}

2^{x} + 2^{x + 3} = 36

2^{x^{2}} \times 4^{x} \times 2 = 4

\frac{500}{100 - e ^{\frac{x}{2}}} = 20

7^{x + 2} = 5764801

3^{2 x} = 4^{(x + 1)}

What is the answer to 3^{x-5}=64*4^x ?
The answer to 3^{x-5}=64*4^x is x=(6ln(2)+5ln(3))/(ln(3)-2ln(2))
Solve for x: 3^{x-5}=64*4^x
The solution is x=(6ln(2)+5ln(3))/(ln(3)-2ln(2))