What is the answer to 5^{-x+2}=11^{7x} ?

The answer to 5^{-x+2}=11^{7x} is x=(2ln(5))/(7ln(11)+ln(5))

Solve for x: 5^{-x+2}=11^{7x}

The solution is x=(2ln(5))/(7ln(11)+ln(5))

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5^{- x + 2} = 1 1^{7 x}

x = \frac{2 ln ( 5 )}{7 ln ( 11 ) + ln ( 5 )}

Decimal Notation

x = 0.17498 \dots

Solution steps

5^{- x + 2} = 1 1^{7 x}

Apply exponent rules

(- x + 2) ln (5) = 7 x ln (11)

Solve

(- x + 2) ln (5) = 7 x ln (11) : x = \frac{2 ln ( 5 )}{7 ln ( 11 ) + ln ( 5 )}

x = \frac{2 ln ( 5 )}{7 ln ( 11 ) + ln ( 5 )}

3^{- 2 x + 1} \cdot 3^{- 2 x - 3} = 3^{- x}

e^{x} + \frac{1}{2} = 0

2^{x - 2} = 64

1.14 (1.0134)^{x} = 4.23

7^{2 x} + 7^{x} - 12 = 0

What is the answer to 5^{-x+2}=11^{7x} ?
The answer to 5^{-x+2}=11^{7x} is x=(2ln(5))/(7ln(11)+ln(5))
Solve for x: 5^{-x+2}=11^{7x}
The solution is x=(2ln(5))/(7ln(11)+ln(5))