What is the answer to solvefor x,16^{2Y^x}=2^{16^x} ?

The answer to solvefor x,16^{2Y^x}=2^{16^x} is x=-(3ln(2))/(ln(Y)-4ln(2))

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solvefor x,16^{2Y^x}=2^{16^x}

solve for

x, 1 6^{2 Y^{x}} = 2^{1 6^{x}}

x = - \frac{3 ln ( 2 )}{ln ( Y ) - 4 ln ( 2 )}

Solution steps

1 6^{2 Y^{x}} = 2^{1 6^{x}}

Apply exponent rules

ln (8) + x ln (Y) = x ln (16)

Solve

ln (8) + x ln (Y) = x ln (16) : x = - \frac{3 ln ( 2 )}{ln ( Y ) - 4 ln ( 2 )}

x = - \frac{3 ln ( 2 )}{ln ( Y ) - 4 ln ( 2 )}

2 5^{x} + 5^{1 + 2 x} = 40

x, 3^{x + 1} = 3^{x} + 18

3^{2 x - 1} = 3

5 (1 0^{2 x} - 2) = 15

5^{n + 10} = 25

What is the answer to solvefor x,16^{2Y^x}=2^{16^x} ?
The answer to solvefor x,16^{2Y^x}=2^{16^x} is x=-(3ln(2))/(ln(Y)-4ln(2))