What is the answer to 9^x+3^{1+2x}=20 ?

The answer to 9^x+3^{1+2x}=20 is x=(ln(5))/(2ln(3))

Solve for x: 9^x+3^{1+2x}=20

The solution is x=(ln(5))/(2ln(3))

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9^{x} + 3^{1 + 2 x} = 20

x = \frac{ln ( 5 )}{2 ln ( 3 )}

Decimal Notation

x = 0.73248 \dots

Solution steps

9^{x} + 3^{1 + 2 x} = 20

Apply exponent rules

2 x ln (3) = ln (5)

Solve

2 x ln (3) = ln (5) : x = \frac{ln ( 5 )}{2 ln ( 3 )}

x = \frac{ln ( 5 )}{2 ln ( 3 )}

9^{x} + 3^{1 + 2 x} = 50

9^{2 x + 5} = 2 7^{x}

4^{3 x - 1} = 3 2^{x}

- 11 e^{- x} = 0

3^{2 x - 1} - 2^{x} = 0

What is the answer to 9^x+3^{1+2x}=20 ?
The answer to 9^x+3^{1+2x}=20 is x=(ln(5))/(2ln(3))
Solve for x: 9^x+3^{1+2x}=20
The solution is x=(ln(5))/(2ln(3))