What is the answer to 16^{8^{-27^{-x}}}=4 ?

The answer to 16^{8^{-27^{-x}}}=4 is x= 1/3

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16^{8^{-27^{-x}}}=4

1 6^{8^{- 2 7^{- x}}} = 4

x = \frac{1}{3}

Decimal Notation

x = 0.33333 \dots

Solution steps

1 6^{8^{- 2 7^{- x}}} = 4

Apply exponent rules

(1 + 3 (- 2 7^{- x})) ln (2) = ln (1)

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

1 + 3 (- 2 7^{- x}) = 0

Solve

1 + 3 (- 2 7^{- x}) = 0 : x = \frac{1}{3}

x = \frac{1}{3}

4^{4 x + 1} = 16

4^{x - 5} = 8^{2 x - 2}

\frac{2 ^{8 - x}}{3 2 ^{x + 12}} = 2^{3 x - 7}

100 = 20 e^{2 t}

- 9 \times 9^{8 \times 5 - 6 x} + 1 = - 25

What is the answer to 16^{8^{-27^{-x}}}=4 ?
The answer to 16^{8^{-27^{-x}}}=4 is x= 1/3
Solve for x: 16^{8^{-27^{-x}}}=4
The solution is x= 1/3