What is the answer to (2^{8-x})/(32^{x+12)}=2^{3x-7} ?

The answer to (2^{8-x})/(32^{x+12)}=2^{3x-7} is x=-5

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(2^{8-x})/(32^{x+12)}=2^{3x-7}

\frac{2 ^{8 - x}}{3 2 ^{x + 12}} = 2^{3 x - 7}

x = - 5

Solution steps

\frac{2 ^{8 - x}}{3 2 ^{x + 12}} = 2^{3 x - 7}

Apply exponent rules

- x - 12 + 20 + 5 (- x - 12) = 3 x - 7

Solve

- x - 12 + 20 + 5 (- x - 12) = 3 x - 7 : x = - 5

x = - 5

Verify Solutions:

x = - 5

True

The solution is

x = - 5

100 = 20 e^{2 t}

- 9 \times 9^{8 \times 5 - 6 x} + 1 = - 25

3^{2 x - 1} = 4^{x}

4^{x - 2} - 6 = 13

2 \times 4^{x} = 64

What is the answer to (2^{8-x})/(32^{x+12)}=2^{3x-7} ?
The answer to (2^{8-x})/(32^{x+12)}=2^{3x-7} is x=-5
Solve for x: (2^{8-x})/(32^{x+12)}=2^{3x-7}
The solution is x=-5