What is the answer to 4^{x-2}-6=13 ?

The answer to 4^{x-2}-6=13 is x=(ln(19))/(2ln(2))+2

Solve for x: 4^{x-2}-6=13

The solution is x=(ln(19))/(2ln(2))+2

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4^{x - 2} - 6 = 13

x = \frac{ln ( 19 )}{2 ln ( 2 )} + 2

Decimal Notation

x = 4.12396 \dots

Solution steps

4^{x - 2} - 6 = 13

Move

6

to the right side

4^{x - 2} = 19

Apply exponent rules

(x - 2) ln (4) = ln (19)

Solve

(x - 2) ln (4) = ln (19) : x = \frac{ln ( 19 )}{2 ln ( 2 )} + 2

x = \frac{ln ( 19 )}{2 ln ( 2 )} + 2

2 \times 4^{x} = 64

5^{n} = 625

5^{x - 1} = 3^{2 x + 1}

201 \cdot 2^{x} = 67

4^{5 x + 1} = 16

What is the answer to 4^{x-2}-6=13 ?
The answer to 4^{x-2}-6=13 is x=(ln(19))/(2ln(2))+2
Solve for x: 4^{x-2}-6=13
The solution is x=(ln(19))/(2ln(2))+2