What is the answer to 201*2^x=67 ?

The answer to 201*2^x=67 is x=-(ln(3))/(ln(2))

Solve for x: 201*2^x=67

The solution is x=-(ln(3))/(ln(2))

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201 \cdot 2^{x} = 67

x = - \frac{ln ( 3 )}{ln ( 2 )}

Decimal Notation

x = - 1.58496 \dots

Solution steps

201 \cdot 2^{x} = 67

Divide both sides by

201

2^{x} = \frac{1}{3}

Apply exponent rules

x ln (2) = ln (\frac{1}{3})

Solve

x ln (2) = ln (\frac{1}{3}) : x = - \frac{ln ( 3 )}{ln ( 2 )}

x = - \frac{ln ( 3 )}{ln ( 2 )}

4^{5 x + 1} = 16

8^{x - 1} = \frac{1}{16 2}

2^{x + 3} - 2^{x + 1} = 12

2 e^{4 x - 6} = 16

What is the answer to 201*2^x=67 ?
The answer to 201*2^x=67 is x=-(ln(3))/(ln(2))
Solve for x: 201*2^x=67
The solution is x=-(ln(3))/(ln(2))