What is the answer to 7^{x^2}=(1/49)^{3x+4} ?

The answer to 7^{x^2}=(1/49)^{3x+4} is x=-2,x=-4

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7^{x^2}=(1/49)^{3x+4}

7^{x^{2}} = (\frac{1}{49})^{3 x + 4}

x = - 2, x = - 4

Solution steps

7^{x^{2}} = (\frac{1}{49})^{3 x + 4}

Apply exponent rules

x^{2} = - 2 (3 x + 4)

Solve

x^{2} = - 2 (3 x + 4) : x = - 2, x = - 4

x = - 2, x = - 4

5^{1 - 2 x} = 3^{x + 3}

e^{x^{2}} = e^{9}

e^{1 - 4 x} = 15

a^{x + 1} - a^{x} = 1

4^{x} - 9 \times 2^{x} + 8 = 0

What is the answer to 7^{x^2}=(1/49)^{3x+4} ?
The answer to 7^{x^2}=(1/49)^{3x+4} is x=-2,x=-4
Solve for x: 7^{x^2}=(1/49)^{3x+4}
The solution is x=-2,x=-4