What is the answer to 5^{1-2x}=3^{x+3} ?

The answer to 5^{1-2x}=3^{x+3} is x=-(3ln(3)-ln(5))/(ln(75))

Solve for x: 5^{1-2x}=3^{x+3}

The solution is x=-(3ln(3)-ln(5))/(ln(75))

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5^{1 - 2 x} = 3^{x + 3}

x = - \frac{3 ln ( 3 ) - ln ( 5 )}{ln ( 75 )}

Decimal Notation

x = - 0.39059 \dots

Solution steps

5^{1 - 2 x} = 3^{x + 3}

Apply exponent rules

(1 - 2 x) ln (5) = (x + 3) ln (3)

Solve

(1 - 2 x) ln (5) = (x + 3) ln (3) : x = - \frac{3 ln ( 3 ) - ln ( 5 )}{ln ( 75 )}

x = - \frac{3 ln ( 3 ) - ln ( 5 )}{ln ( 75 )}

e^{x^{2}} = e^{9}

e^{1 - 4 x} = 15

a^{x + 1} - a^{x} = 1

4^{x} - 9 \times 2^{x} + 8 = 0

x, 5^{2 x - 3} = 3^{3 x + 4}

What is the answer to 5^{1-2x}=3^{x+3} ?
The answer to 5^{1-2x}=3^{x+3} is x=-(3ln(3)-ln(5))/(ln(75))
Solve for x: 5^{1-2x}=3^{x+3}
The solution is x=-(3ln(3)-ln(5))/(ln(75))