What is the answer to 3^{2+p}-3^{1+p}=20(3)-6 ?

The answer to 3^{2+p}-3^{1+p}=20(3)-6 is p=2

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3^{2+p}-3^{1+p}=20(3)-6

3^{2 + p} - 3^{1 + p} = 20 (3) - 6

p = 2

Solution steps

3^{2 + p} - 3^{1 + p} = 20 (3) - 6

Factor

3^{2 + p} - 3^{1 + p} : 2 \cdot 3^{1 + p}

2 \cdot 3^{1 + p} = 54

Divide both sides by

2

3^{1 + p} = 27

Apply exponent rules

1 + p = 3

Solve

1 + p = 3 : p = 2

p = 2

7^{x + 1} = 2^{x}

e^{x} = e^{x}

2 \cdot 3^{5 x} = 1

8 1^{x^{2}} = 2 7^{x}

4^{x} = 47

What is the answer to 3^{2+p}-3^{1+p}=20(3)-6 ?
The answer to 3^{2+p}-3^{1+p}=20(3)-6 is p=2
Solve for p: 3^{2+p}-3^{1+p}=20(3)-6
The solution is p=2