What is the answer to 4^x=47 ?

The answer to 4^x=47 is x=(ln(47))/(2ln(2))

The solution is x=(ln(47))/(2ln(2))

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4^x=47

4^{x} = 47

x = \frac{ln ( 47 )}{2 ln ( 2 )}

Decimal

x = 2.77729 \dots

Solution steps

4^{x} = 47

Apply exponent rules

x ln (4) = ln (47)

Solve

x ln (4) = ln (47) : x = \frac{ln ( 47 )}{2 ln ( 2 )}

x = \frac{ln ( 47 )}{2 ln ( 2 )}

4^{x} = 27

n, (x^{3})^{3} = x^{n}

4^{x} \times 3^{2 x} = 6

5 x = 4^{x + 1}

3^{4 - 2 x} = 9^{2 x}