What is the answer to 4^x=9^{x-2} ?

The answer to 4^x=9^{x-2} is x=-(2ln(3))/(ln(2)-ln(3))

Solve for x: 4^x=9^{x-2}

The solution is x=-(2ln(3))/(ln(2)-ln(3))

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4^{x} = 9^{x - 2}

x = - \frac{2 ln ( 3 )}{ln ( 2 ) - ln ( 3 )}

Decimal

x = 5.41902 \dots

Solution steps

4^{x} = 9^{x - 2}

Apply exponent rules

x ln (4) = (x - 2) ln (9)

Solve

x ln (4) = (x - 2) ln (9) : x = - \frac{2 ln ( 3 )}{ln ( 2 ) - ln ( 3 )}

x = - \frac{2 ln ( 3 )}{ln ( 2 ) - ln ( 3 )}

10 e - 0.0 3^{t} = 4

3 4^{x + 1} = 1

2^{2 x} = 6

3^{\frac{x}{5}} = 2^{4 x - 2}

2^{x + 1} - 2^{x} = 8

What is the answer to 4^x=9^{x-2} ?
The answer to 4^x=9^{x-2} is x=-(2ln(3))/(ln(2)-ln(3))
Solve for x: 4^x=9^{x-2}
The solution is x=-(2ln(3))/(ln(2)-ln(3))