What is the answer to 3^x=2^{2-x} ?

The answer to 3^x=2^{2-x} is x=(2ln(2))/(ln(6))

Solve for x: 3^x=2^{2-x}

The solution is x=(2ln(2))/(ln(6))

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3^{x} = 2^{2 - x}

x = \frac{2 ln ( 2 )}{ln ( 6 )}

Decimal

x = 0.77370 \dots

Solution steps

3^{x} = 2^{2 - x}

Apply exponent rules

x ln (3) = (2 - x) ln (2)

Solve

x ln (3) = (2 - x) ln (2) : x = \frac{2 ln ( 2 )}{ln ( 6 )}

x = \frac{2 ln ( 2 )}{ln ( 6 )}

2 e^{3 x} = 5 e^{8 x}

- 3 e^{- 3 t} = 1

4^{2 x} = \frac{1}{64}

3^{3 x - 1} = 6^{x - 5}

e^{x} - e = 0

What is the answer to 3^x=2^{2-x} ?
The answer to 3^x=2^{2-x} is x=(2ln(2))/(ln(6))
Solve for x: 3^x=2^{2-x}
The solution is x=(2ln(2))/(ln(6))