What is the answer to (4^x)/(3^x)= 9/16 ?

The answer to (4^x)/(3^x)= 9/16 is x=(ln(9/16))/(2ln(2)-ln(3))

Solve for x: (4^x)/(3^x)= 9/16

The solution is x=(ln(9/16))/(2ln(2)-ln(3))

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\frac{4 ^{x}}{3 ^{x}} = \frac{9}{16}

x = \frac{ln ( \frac{9}{16} )}{2 ln ( 2 ) - ln ( 3 )}

Decimal

x = - 2

Solution steps

\frac{4 ^{x}}{3 ^{x}} = \frac{9}{16}

Apply exponent rules

(lo g_{3} (4) x - x) ln (3) = ln (\frac{9}{16})

Solve

(lo g_{3} (4) x - x) ln (3) = ln (\frac{9}{16}) : x = \frac{ln ( \frac{9}{16} )}{2 ln ( 2 ) - ln ( 3 )}

x = \frac{ln ( \frac{9}{16} )}{2 ln ( 2 ) - ln ( 3 )}

Verify Solutions:

x = \frac{ln ( \frac{9}{16} )}{2 ln ( 2 ) - ln ( 3 )}

True

The solution is

x = \frac{ln ( \frac{9}{16} )}{2 ln ( 2 ) - ln ( 3 )}

e^{- \frac{π x}{1 - x ^{2}}} = 0.05

6 4^{- x + 39} = 12 8^{x}

1 7^{x} = 4.7

0.3 \times e^{3 x} = 27

3 6^{x} - 6 \cdot 6^{x} = - 9

What is the answer to (4^x)/(3^x)= 9/16 ?
The answer to (4^x)/(3^x)= 9/16 is x=(ln(9/16))/(2ln(2)-ln(3))
Solve for x: (4^x)/(3^x)= 9/16
The solution is x=(ln(9/16))/(2ln(2)-ln(3))