What is the answer to e^{-(pix)/(sqrt(1-x^2))}=0.05 ?

The answer to e^{-(pix)/(sqrt(1-x^2))}=0.05 is x=sqrt((ln^2(0.05))/(pi^2+ln^2(0.05)))

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e^{-(pix)/(sqrt(1-x^2))}=0.05

e^{- \frac{π x}{1 - x ^{2}}} = 0.05

x = \frac{ln ^{2} ( 0.05 )}{π ^{2} + ln ^{2} ( 0.05 )}

Decimal

x = 0.69010 \dots

Solution steps

e^{- \frac{π x}{1 - x ^{2}}} = 0.05

Apply exponent rules

- \frac{π x}{1 - x ^{2}} = ln (0.05)

Solve

- \frac{π x}{1 - x ^{2}} = ln (0.05) : x = \frac{ln ^{2} ( 0.05 )}{π ^{2} + ln ^{2} ( 0.05 )}

x = \frac{ln ^{2} ( 0.05 )}{π ^{2} + ln ^{2} ( 0.05 )}

6 4^{- x + 39} = 12 8^{x}

1 7^{x} = 4.7

0.3 \times e^{3 x} = 27

3 6^{x} - 6 \cdot 6^{x} = - 9

2^{3 x - 1} \cdot 4^{2 x + 3} = 8^{3 - x}

What is the answer to e^{-(pix)/(sqrt(1-x^2))}=0.05 ?
The answer to e^{-(pix)/(sqrt(1-x^2))}=0.05 is x=sqrt((ln^2(0.05))/(pi^2+ln^2(0.05)))