What is the answer to 2^{3x-1}*4^{2x+3}=8^{3-x} ?

The answer to 2^{3x-1}*4^{2x+3}=8^{3-x} is x= 2/5

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2^{3x-1}*4^{2x+3}=8^{3-x}

2^{3 x - 1} \cdot 4^{2 x + 3} = 8^{3 - x}

x = \frac{2}{5}

Decimal Notation

x = 0.4

Solution steps

2^{3 x - 1} \cdot 4^{2 x + 3} = 8^{3 - x}

Apply exponent rules

3 x - 1 + 2 (2 x + 3) = 3 (3 - x)

Solve

3 x - 1 + 2 (2 x + 3) = 3 (3 - x) : x = \frac{2}{5}

x = \frac{2}{5}

3^{5 x} 9^{x^{2}} = 27

3^{2 x} = 1

3^{x + \frac{1}{2}} \times 3^{x - 2} = 1

3^{4 x} = 7^{2 - 5 x}

2^{3 k - 1} \cdot 2^{5 k - 7} = 16

What is the answer to 2^{3x-1}*4^{2x+3}=8^{3-x} ?
The answer to 2^{3x-1}*4^{2x+3}=8^{3-x} is x= 2/5
Solve for x: 2^{3x-1}*4^{2x+3}=8^{3-x}
The solution is x= 2/5